Python Program to Check Armstrong Number of n digits

Source Code:

num = 1634

# Changed num variable to string, 
# and calculated the length (number of digits)
order = len(str(num))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** order
   temp //= 10

# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")

Output:

Screen-shot